8A 5

Sensory Systems and the Detection of Light

Explain how a rod detects light: rhodopsin, sodium channels and hyperpolarisation, leading to impulses in optic neurones.

YOUR SPECIFICATION

What you need to know

  • 8.8Rods detect light using , opsin, , sodium ions, cation channels and , leading to in optic neurones.
Pearson specification · Issue 2, p. 37

Cones are not required. The rod hyperpolarises. It does not fire the action potential. Do not import the axon sodium spike into the rod.

By the end, you should be able to…

  • Describe rhodopsin as opsin plus retinal.
  • Explain why light closes sodium channels and hyperpolarises the rod.
  • State where the action potentials are produced.
SPECIFICATION-ALIGNED LEARNING

Build your understanding

Rhodopsin is the light-sensitive pigment

Rods are photoreceptors in the retina. They work in dim light. Their pigment is , made of the protein opsin and a molecule called . In the dark, retinal is in the cis form and is bound to opsin. Many rods share connections toward one optic neurone, which is why rods detect dim light but do not give a sharp picture. Acuity is not the specification focus. The pigment chemistry is.

The National Eye Institute describes photoreceptors turning light into electrical signals. The specification tells you the electrical direction in a rod, which that overview does not. Learn the direction here.

Dark current, then a closing of channels

In the dark, cation channels in the rod membrane are open. Sodium ions enter. The rod is relatively depolarised and releases a transmitter onto the next cell. This resting inflow is sometimes called the . It is the opposite of the resting axon, which is waiting to open sodium channels.

When light is absorbed, retinal changes from cis to trans and opsin changes shape. Rhodopsin is bleached. A short cascade, which you do not need to name by enzyme, closes the sodium channels. Sodium entry falls. The inside of the rod becomes more negative. That is . The rod then releases less transmitter.

The spike is one cell later

The change in transmitter alters the bipolar cell, and ganglion cells produce . Those impulses travel in the optic nerve. The specification line is exact: hyperpolarisation of the rod leads to action potentials in the optic neurones. If you write that the rod depolarises and fires a spike, you have used the axon lesson in the wrong cell.

In the dark the pigment is rebuilt and the channels can open again. Bright light bleaches many rods, which is why vision is poor for a moment when you walk into a dark room. That recovery is useful context. It is not a second pathway to memorise.

Follow the process

In the dark: cation channels are open → sodium enters → the rod is relatively depolarised → it releases transmitter. In the light: retinal changes from cis to trans and opsin changes shape → rhodopsin is bleached → sodium channels close → sodium entry falls → the rod hyperpolarises → less transmitter is released → bipolar cells change, and ganglion cells fire action potentials in the optic nerve. The rod itself does not fire that spike. This is the opposite of an axon, where a stimulus opens sodium channels.

In the dark, sodium channels in the rod are open and transmitter is released. In the light, retinal changes shape, sodium channels close, the rod hyperpolarises and less transmitter is released. Action potentials are produced in the optic neurone. In the light the rod hyperpolarises. The spike is in the next cell.Outer segment (rhodopsin discs), inner segment, then the synapse with a bipolar cell.DarkNa+​ inrhodopsin intactNa+​ channels open: rod depolarisedtransmitter releasedbipolar cell inhibitedLightlightNa+​ channels closeretinal changes shape; rhodopsinbreaks down: rod hyperpolarisedless transmitter releasedbipolar cell depolarises → optic neurone firesRhodopsin is opsin plus retinal. The rod itself does not fire the action potential.

NOT: the rod does not fire the action potential, and this point is not about cones.

  1. Rhodopsin is opsin plus retinal
  2. Light closes sodium channels
  3. The rod hyperpolarises
  4. The spike is in the optic neurone

Two traps this diagram blocks

  • Do not say the rod fires an impulse down the optic nerve.
  • Do not describe this as the same sodium entry as an axonal action potential.

From the diagram alone

Question

Explain how light changes a rod, and state where the action potentials occur. [4]

Show a model answer

Light changes retinal in rhodopsin, sodium channels close and the rod hyperpolarises, so less transmitter is released. Action potentials are then produced in the optic neurone, not in the rod.

EXAM TIPS & ADVICE

Make your reasoning visible

Build the explanation

X happens because Y, leading to Z. X: a rod hyperpolarises in the light. Y: light closes its sodium channels, so the stops. Z: less transmitter is released, and the next cells produce the in the optic nerve. Incomplete: “The rod fires an impulse down the optic nerve.” Improved: “Light bleaches , sodium channels close, and the rod becomes more negative. The spike is in the optic neurone, not in the rod.”

Light closes sodium channels

Opposite of the axon spike. , less transmitter.

Name both parts of the pigment

Rhodopsin is opsin plus . Light changes retinal’s shape.

Avoid this misconception

The claim: Light opens sodium channels in the rod and the rod fires an action potential down the optic nerve.

The correction: Light causes sodium channels in the rod to close. The rod hyperpolarises and releases less transmitter. Action potentials are produced in the optic neurones.

BEFORE YOU START · NERVOUS SYSTEM

Why does a rod go more negative when light hits it?

In the dark, sodium ions flow into a rod all the time. Light changes the shape of retinal in rhodopsin, the sodium channels close, and the rod hyperpolarises. The action potentials come one cell later, in the optic neurone.

What the model shows

One rod, its pigment and channels, and the optic neurone it signals to, in the dark, in dim and bright light, and recovering in the dark.

What to look for

Which way the rod’s voltage moves, what happens to transmitter release, and where the spikes appear.

What it tells us

Light closes Na⁺ channels and hyperpolarises the rod. Bleached rhodopsin must be rebuilt in the dark. The rod does not fire action potentials.

Be careful what you claim

Illustrative values; recovery sped up.

Try it in the model: press Play, then switch to Dim light.

SPECIFICATION 8.8 · MODEL

How a rod detects light

Follow one rod in the dark, in dim and bright light and while it recovers in the dark: rhodopsin, the Na⁺ channels, the rod’s voltage and the action potentials in the optic neurone. Values are illustrative and recovery is sped up.

What you see
  • A rod: the outer segment with discs of rhodopsin (purple when ready, pale when bleached), Na⁺ channels in its membrane, and the synaptic terminal releasing transmitter onto a bipolar cell and then an optic (ganglion) neurone.
  • A close-up of one rhodopsin molecule with retinal in its cis or trans form, and a graph of the rod’s membrane potential with the optic neurone’s action potentials below it.
How to use it
  • Choose Dark, Dim or Bright light, press Flash a dim light for a short test flash, and turn on the drug that holds the Na⁺ channels open. Play runs the clock.
What it shows
  • Rhodopsin is opsin plus retinal; light changes retinal from cis to trans and bleaches the pigment (8.8).
  • Light closes cation channels, so the rod hyperpolarises and releases less transmitter, leading to action potentials in the optic neurones (8.8).
Limits of the model
  • Values are illustrative and rebuilding rhodopsin is sped up about tenfold. The cascade between rhodopsin and the channels is not named, as the specification does not require it.
  • The bipolar and ganglion cells are simplified to one pathway in which less transmitter means more firing. Cones are not included.

Guided tour · step 1 of 9

What to do
  1. In Rod, just below these steps, keep Light on Dark (options: Dark, Dim light, Bright light).
  2. Press Play and watch the simulator for a few seconds.
Why

Cation channels in the rod membrane are open, so Na⁺ ions flow in (the dark current). The rod sits relatively depolarised at about −40 mV and releases transmitter all the time.

Rod

Light
Hold Na⁺ channels open (drug)
Rod-40 mV
Rhodopsin ready100%
Optic neurone5 Hz

Questions

Rhodopsin is made of which two parts?
What happens in a rod when light is absorbed?
Where are the action potentials of this pathway produced?
RETRIEVE · APPLY · CHECK

Check your understanding

Try each question before opening the suggested answer.

Check your understanding (continued)

  1. Practice question

    Retrieval and explanation · suggested answer

    What are the two components of rhodopsin?

    Show suggested answer

    The protein opsin and retinal.

  2. Practice question

    Retrieval and explanation · suggested answer

    What happens to sodium channels in a rod when light is absorbed?

    Show suggested answer

    They close, so less sodium enters and the rod hyperpolarises.

  3. Practice question

    Retrieval and explanation · suggested answer

    Where are the action potentials of this pathway produced?

    Show suggested answer

    In the optic neurones, not in the rod itself.

  4. Practice question

    Retrieval and explanation · suggested answer

    Why do rods give poor detail even though they are sensitive?

    Show suggested answer

    Many rods converge onto the same pathway, so the brain cannot tell which rod absorbed the light.

STRETCH QUESTION

Take the idea further

Apply the same specification knowledge to an unfamiliar problem. Any extra assumptions are supplied in the question.

Stretch question

A drug holds rod sodium channels open even after rhodopsin has bleached. What happens to the rod’s membrane potential and to transmitter release when the light comes on? Assume the optic neurones are otherwise normal.

Show a hint

The light signal is the closing, not the pigment name alone.

Explore the reasoning

If the channels cannot close, sodium keeps entering, the rod does not hyperpolarise, and transmitter release does not fall. The optic neurones therefore do not receive the change that would make them alter their firing. Bleaching of the pigment is not enough if the channel step is blocked. This is a supplied drug effect, not a medicine to know.

RECALL

Recall this lesson

Lesson recall questions

5 of 17 recall questions for 8.80 of 5 rated0 secure

Question 1 of 5: How does hyperpolarisation of a rod lead to action potentials in optic neurones?

018.8Structure

Rod cells and rhodopsin

Practice question

Retrieval and explanation · suggested answer

How does hyperpolarisation of a rod lead to action potentials in optic neurones?

Try this from memory first.

Practise more of these specification points

Beyond the classroom

Put your biology to work

Explore where these ideas appear in the world. Enrichment, not extra required recall.

MedicineResearch

Photoreceptors start the electrical story

8A · Sensory Systems and the Detection of LightThe National Eye Institute says the retina is a light-sensitive layer and that photoreceptors turn light into electrical signals. It does not mention rhodopsin, retinal, or hyperpolarisation. Those…Specification 8.8Read & use the scienceClose article

Why this matters

The National Eye Institute says the retina is a light-sensitive layer and that photoreceptors turn light into electrical signals. It does not mention rhodopsin, retinal, or hyperpolarisation. Those names are the specification. Use the page only to remember that the eye’s job is a signal, then write the rod mechanism properly. 8.8: rhodopsin, closing of sodium channels, hyperpolarisation, then action potentials in optic neurones. A behaviour or symptom is the output of a pathway, not a direct recording of ion movement in one axon or synapse.

Back to the specification

Pearson Edexcel IAL Biology · Issue 2, February 2021 · Unit 5, pp. 35–38. The application extends beyond required recall.

  • 8.8 Rod cells, rhodopsin and visual signalling.
Read the Pearson specification

Use the science

Why is an answer that only says “the retina detects light” short of 8.8?

Explore a possible response

It misses opsin and retinal, the closing of sodium channels, hyperpolarisation of the rod, and the fact that the spikes are in the optic neurones.

Explore the source

ResearchMedicine

Dark adaptation is more than pupil size

8A · Sensory Systems and the Detection of LightNEI researchers studied how rod photoreceptors in mice adjust their sensitivity when light conditions change. Rods are especially useful in dim light, and the study followed movement of…Specification 8.8Read & use the scienceClose article

Why this matters

NEI researchers studied how rod photoreceptors in mice adjust their sensitivity when light conditions change. Rods are especially useful in dim light, and the study followed movement of a signalling protein called transducin inside those cells. This is beyond the required rhodopsin–retinal–channel sequence, but it reinforces that vision changes within the retina as well as at the pupil. A dilated pupil lets more light reach the retina; it does not itself restore the molecular state of a bleached pigment or explain every minute of dark adaptation. The mouse result is a research clue, not a direct measurement of one student’s night vision.

Back to the specification

Pearson Edexcel IAL Biology · Issue 2, February 2021 · Unit 5, pp. 35–38. The application extends beyond required recall.

  • 8.8 Rod cells, rhodopsin and visual signalling.
Read the Pearson specification

Use the science

Why could two eyes with equally wide pupils still differ in sensitivity to dim light?

Explore a possible response

Pupil diameter controls light entry, but the state and number of rod photoreceptors and their signalling machinery determine how that light is converted to neural signals.

Explore the source

Browse all Unit 5 connections →
END OF THE LESSON

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