YOUR SPECIFICATION

What you need to know

  • 6.2Cell counts, , mass and optical () methods.
Pearson specification · Issue 2, p. 31

k from those numbers is 6A 3. Liquid-culture method and ethics are CP13. Colourimeter brand names are not required.

By the end, you should be able to…

  • List the four specified methods.
  • Distinguish a from a .
  • Explain why turbidity and mass can overestimate living cells.
SPECIFICATION-ALIGNED LEARNING

Build your understanding

Total versus viable

A cell count with a counting chamber records numbers in a known volume, living and dead: a . serially dilutes the culture, spreads a known volume on agar, counts colonies after incubation, and multiplies by the dilution factor to give per cm³: a .

exists so that colonies are separate enough to count, and so that you can scale back to the original density. One colony is treated as one CFU, which assumes each colony grew from one cell — a stated assumption, not a photograph of that cell.

Mass and turbidity

Mass, especially dry mass, measures harvested and avoids variable water in wet mass. It includes dead material and destroys that sample. uses a colorimeter: more cells scatter more light, so absorbance of the mixed broth rises. It is fast and can be repeated, but dead cells still scatter light.

Mix the culture before each optical or count sample so settled cells do not bias the reading. A blank of sterile medium sets the zero. Absorbance is not itself a cell number until you calibrate, and even then it is not a viable count.

Choose for the question

If the question wants living cells, dilution plating is the method that matches. If it wants a quick time course in one flask, turbidity is practical and must be evaluated. If it wants biomass, mass is honest about water. If it wants a microscope number today, a chamber count will do and will include corpses.

Fictional plating example: 62 colonies from 0.10 cm³ of a 10⁻⁴ dilution. CFU cm⁻³ = 62 × 10 × 10⁴ = 6.2 × 10⁶. Those numbers are for practising the scale factor, not a result to copy.

A counting chamber gives a total count, living and dead. Dilution plating gives colony-forming units, a viable count. The worked plate is 62 colonies from 0.10 cm³ of a 10⁻⁴ dilution, which is 6.2 × 10⁶ CFU per cm³. Dry mass and turbidity include dead material. Measuring microbial growth: viable or total countsOnly a method that needs cells to grow counts living cells alone.Dilution platingviable count (CFU)each colony grew fromone living cellCounting chambertotal countcells counted in gridsquares; dead ones tooTurbiditytotal, not viablea colorimeter reads howcloudy the culture isDry mass0.42 gtotal biomasscells dried and weighed;living and dead includedWorked example: 62 colonies from 0.10 cm3​ of a 10−4​ dilution62 ÷ 0.10 × 104​ = 6.2 × 106​ CFU per cm3​ of the original cultureTurbidity, dry mass and counting chambers include dead cells. Only plating gives a viable count.

NOT: only dilution plating estimates living colony-forming units. The other three include dead cells or non-living biomass.

  1. Worked plate: 62 colonies from 0.10 cm³ of a 10⁻⁴ dilution
  2. CFU cm⁻³ = 62 × 10 × 10⁴ = 6.2 × 10⁶
  3. One colony is assumed to come from one cell
  4. Mix the culture and zero the colorimeter with sterile medium
  5. Absorbance is not a cell number until it is calibrated

Two traps this diagram blocks

  • Do not call a colorimeter reading a count of living cells.
  • Do not forget to scale both the volume and the dilution.

From the diagram alone

Question

62 colonies grow from 0.10 cm³ of a 10⁻⁴ dilution. Calculate the number of CFU per cm³ and state what this method counts that a turbidity reading does not. [4]

Show a model answer

Per cm³ the colony count is multiplied by 10, and the dilution factor is 10⁴, so CFU cm⁻³ = 62 × 10 × 10⁴ = 6.2 × 10⁶. Plating estimates viable cells. Turbidity also records dead cells, because they still scatter light.

What each method actually records
MethodLiving only?A limitation
Cell countNoDead cells included; small volumes
Dilution platingYes (CFU)Slow; assumes one cell per colony
MassNoIncludes dead biomass; destructive
TurbidityNoDead cells still scatter light
EXAM TIPS & ADVICE

Make your reasoning visible

Say viable or total

“Count” alone is ambiguous.

Show the dilution arithmetic

Colonies × (1 / volume plated) × dilution factor.

Key explanations

  • The calculation assumes one colony grew from one cell. Clumps break that assumption.

Avoid this misconception

The claim: All four methods count living bacteria.

The correction: Only estimates viable CFUs. Cell counts, mass and include dead cells or non-living .

BEFORE YOU START · SERIAL DILUTION AND PLATE COUNTS

How many living bacteria are in a drop of broth?

A broth culture can hold millions of bacteria in every cm³: far too many to count directly. Diluting it in steps and growing a small sample on agar turns that into a number you can count.

What the model shows

A made-up broth culture, a series of tenfold dilutions, and agar plates spread with 0.10 cm³ from the tubes you choose. After incubation each living cell has grown into a colony.

What to look for

Which plates have too many colonies to count, which have too few, and which one falls in the 30 to 300 range that you can count reliably.

What it tells us

Counting the colonies on one good plate and multiplying back by the volume and the dilution factor estimates the living cells in the original broth, in colony-forming units per cm³.

Be careful what you claim

It assumes each colony grew from one cell, and the count varies by chance from plate to plate. Dead cells never form colonies, so this is a viable count, not a total count.

Try it in the model: make all six dilutions, spread plates from 10⁻³, 10⁻⁴ and 10⁻⁵, then incubate them.

SPECIFICATION 6.2 · MODEL

Serial dilution and plate counts

A fictional broth holds millions of bacteria per cm³. Dilute it tenfold six times, spread 0.10 cm³ from the tubes you choose, incubate, then count a plate with 30–300 colonies and scale back to CFU per cm³.

What you see
  • A broth culture and six dilution tubes, 10⁻¹ to 10⁻⁶, each shaded by its cell density.
  • An agar plate under each tube once it is spread, and the colonies after incubation.
  • Plates marked as too many to count, countable (30–300) or too few.
How to use it
  • Make the series one transfer at a time, choose which tubes to plate, then incubate.
  • Pick a countable plate and scale its count back to CFU per cm³ of the broth.
  • Start a new broth to practise with a different density.
What it shows
  • Why serial dilution is needed: separate colonies, and a known factor to scale back by (6.2).
  • How colonies × (1 / volume) × dilution factor gives CFU cm⁻³.
  • That dilution plating is a viable count, unlike a counting chamber, mass or turbidity.
Limits of the model
  • Fictional broth and numbers. Each colony is assumed to grow from one cell; clumps make plating underestimate cells.
  • Colony numbers include chance (Poisson) variation. Real practice uses replicate plates and averages them.
  • Pipetting error, and cells that cannot grow on this medium, are left out.

Guided tour · step 1 of 7

What to do
  1. In the simulator, mix the broth, then transfer 1 cm³ into 9 cm³ of sterile water, six times, to make 10⁻¹ to 10⁻⁶.
  2. Or press Make the rest in Dilute and plate, just below these steps.
Why

Each tenfold step divides the density by 10. The original broth is far too dense to give separate colonies.

Dilute and plate

Count and scale back

Spread at least one plate and incubate to see colonies.

Tubes made0 of 6
Plates spread0
Counted plate—

Questions

Lesson example (fictional): 62 colonies grew from 0.10 cm³ of the 10⁻⁴ dilution. What is the density of the original culture in CFU cm⁻³?

A counting chamber on the same broth gives about 8.3 × 10⁶ cells cm⁻³, higher than the plate count of 6.2 × 10⁶ CFU cm⁻³. What is the best explanation?

Why 30–300?

Above about 300 colonies, neighbours merge and compete, so counts are too low and hard to make. Below 30, a few chance cells make a big percentage difference. The undiluted broth would give a lawn, which is why the series is needed. Turbidity and dry mass (also 6.2) are faster but include dead cells.

RETRIEVE · APPLY · CHECK

Check your understanding

Try each question before opening the suggested answer.

Check your understanding (continued)

  1. Practice question

    Retrieval and explanation · suggested answer

    List the four specified methods of measuring microbial growth.

    Show suggested answer

    Cell counts, dilution plating, mass, and optical methods (turbidity).

  2. Practice question

    Retrieval and explanation · suggested answer

    Compare a total cell count with a viable count.

    Show suggested answer

    A chamber count includes living and dead cells. Dilution plating counts cells that form colonies, so it is a viable count.

  3. Practice question

    Retrieval and explanation · suggested answer

    Why can turbidity overestimate living numbers?

    Show suggested answer

    Dead cells still scatter light, so absorbance stays high after cells die.

  4. Practice question

    Retrieval and explanation · suggested answer

    Why use dry mass rather than wet mass?

    Show suggested answer

    Dry mass removes variable water, so the figure better reflects cell material.

STRETCH QUESTION

Take the idea further

Apply the same specification knowledge to an unfamiliar problem. Any extra assumptions are supplied in the question.

Stretch question

Fictional data: absorbance stays high while CFU cm⁻³ falls. Interpret, and say which 6.3 phase this pattern fits.

Show a hint

What each method includes.

Explore the reasoning

Cells are dying but still scattering light, so turbidity lags the viable count. That mismatch is expected as a culture enters death phase. k must not be calculated from the absorbance plateau.

RECALL

Recall this lesson

Lesson recall questions

5 of 16 recall questions for 6.20 of 5 rated0 secure

Question 1 of 5: Compare a total cell count with a viable count from dilution plating.

016.2Compare

Measuring microbial growth

Practice question

Retrieval and explanation · suggested answer

Compare a total cell count with a viable count from dilution plating.

Try this from memory first.

Practise more of these specification points

Beyond the classroom

Put your biology to work

Explore where these ideas appear in the world. Enrichment, not extra required recall.

ResearchMedicineCareers

Why a brewery still plates as well as reading a meter

6A · Measuring the Growth of Bacterial CulturesThe Microbiology Society treats culture and counting as basic microbial work. A turbidity meter is quick on a tank; a plate count still asks how many cells can…Specification 6.2Read & use the scienceClose article

Why this matters

The Microbiology Society treats culture and counting as basic microbial work. A turbidity meter is quick on a tank; a plate count still asks how many cells can grow. School colorimeter curves are the same distinction at flask scale. Factory numbers are not your CP13 results. Optical density records how much light a suspension scatters; it does not identify live cells. A colony-forming count measures cells or clumps able to grow under the chosen plate conditions, so the two values need not agree.

Back to the specification

Pearson Edexcel IAL Biology · Issue 2, February 2021 · Unit 4, pp. 29–32. The application extends beyond required recall.

  • 6.2 understand the different methods of measuring the growth of microorganisms, as illustrated by cell counts, dilution plating, mass and optical methods (turbidity)
Read the Pearson specification

Use the science

If a meter reading is convenient, why might an examiner still ask for dilution plating?

Explore a possible response

The question may need a viable count. Convenience does not turn turbidity into CFU.

Explore the source

CareersResearch

Cloudy is not the same as alive

6A · Measuring the Growth of Bacterial CulturesOptical density estimates how much light a microbial suspension scatters. A published study found that stress and reduced viability changed the relationship between optical density and cell count…Specification 6.2Read & use the scienceClose article

Why this matters

Optical density estimates how much light a microbial suspension scatters. A published study found that stress and reduced viability changed the relationship between optical density and cell count in Listeria. A food microbiologist therefore calibrates an instrument for the organism and conditions being tested, and may check a culture by dilution plating. Dead cells and particles can still scatter light; a colony count instead records units able to grow on the chosen medium. Neither method is a perfect census, because clumps and growth conditions affect the result. The lesson’s methods answer different questions, even when both produce a number.

Back to the specification

Pearson Edexcel IAL Biology · Issue 2, February 2021 · Unit 4, pp. 29–32. The application extends beyond required recall.

  • 6.2 understand the different methods of measuring the growth of microorganisms, as illustrated by cell counts, dilution plating, mass and optical methods (turbidity)
Read the Pearson specification

Use the science

If a disinfectant kills many cells without immediately clearing the suspension, how might turbidity and viable plate count differ?

Explore a possible response

Turbidity may remain high because dead cells still scatter light, while the viable colony count should fall.

Explore the source

Browse all Unit 4 connections →
END OF THE LESSON

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