7A 3

The Krebs Cycle

Explain the link reaction and the Krebs cycle as the mitochondrial stages that finish oxidising the carbohydrate fragment.

YOUR SPECIFICATION

What you need to know

  • 7.3 and : carbon dioxide by , a little by , and by . These steps are in . Other compound names are not required.
Pearson specification · Issue 2, p. 35

Names of the acids in the cycle are not required. Oxaloacetate and citrate appear only as a labelled extra for the carbon count, not as required recall. Acetyl coenzyme A is the usual label for the two-carbon carrier only. Oxidative phosphorylation is 7A 4. The usual per-turn counts below are a balance for calculations, not a list of intermediates.

By the end, you should be able to…

  • Locate the link reaction and Krebs cycle in the mitochondrial matrix.
  • Describe decarboxylation and dehydrogenation without naming cycle acids.
  • State the usual products of one turn.

Open the respiration modelOpen the aerobic route and select the link reaction and the Krebs cycle. Oxygen is not a reactant inside the cycle.

SPECIFICATION-ALIGNED LEARNING

Build your understanding

The link reaction, once per pyruvate

from enters the mitochondrial matrix. Glycolysis itself stays in the . In the , pyruvate is decarboxylated: a molecule of carbon dioxide is removed. It is also dehydrogenated: hydrogen is accepted by NAD, so is formed. The remaining two-carbon acetyl group is carried by into the .

The usual name for that carrier-bound group is . The specification says names of the other compounds are not required, so do not spend memory on the acids inside the cycle. Do remember carbon dioxide, reduced NAD, and the two-carbon hand-off.

The cycle completes the oxidation

In the Krebs cycle the two-carbon group is taken in and, during one turn, two molecules of carbon dioxide are released by . That is the rest of the carbon from that fragment of the carbohydrate. produces reduced NAD and . One is formed by . Coenzyme A is freed to collect another acetyl group.

The usual school balance for one turn is two CO₂, three reduced NAD, one reduced FAD and one ATP. Use it if a question asks for a count. It is still not permission to recite citrate and the rest. Per there are two pyruvates, so the link reaction and the cycle both happen twice. The reduced have not yet made the large ATP yield; they carry hydrogen to the next lesson.

Carbon dioxide here is a metabolic waste

Every decarboxylation in these two stages is a source of the carbon dioxide in the overall equation. Breathing then removes that gas from the blood. The lung did not perform the Krebs cycle. If you write “the lungs respire glucose”, you have swapped ventilation for this matrix chemistry.

Without a supply of oxidised NAD and FAD the cycle stops. Those oxidised coenzymes return only if the is running. That is why the Krebs cycle is an aerobic-stage pathway even though oxygen is not a reactant written inside the cycle itself.

Follow the process

Link reaction, in the matrix, once per pyruvate: pyruvate enters → decarboxylation removes one CO₂ and dehydrogenation reduces NAD → the remaining two-carbon group is carried by coenzyme A as acetyl coenzyme A. No ATP is made in the link reaction. Krebs cycle, one turn of that fragment: the two-carbon group is accepted → two decarboxylations release the rest of its carbon as CO₂ → dehydrogenations produce reduced NAD and reduced FAD → one ATP is made by substrate-level phosphorylation → the acceptor molecule is regenerated, so another fragment can enter. Per glucose, both stages run twice. Names of the acids in the cycle are not required.

Follow the process (continued)

Extra, not required: the four-carbon acceptor is called . It joins the two-carbon acetyl group to make citrate, which has six carbons, and oxaloacetate is regenerated at the end of the turn. Use those two names only if a question shows the carbon count. Do not memorise the other acids.

In the mitochondrial matrix, pyruvate loses carbon dioxide in the link reaction and a two-carbon group enters the Krebs cycle on coenzyme A. One turn releases carbon dioxide, reduced NAD, reduced FAD and a little ATP. The matrix releases carbon dioxide and loads the coenzymesThe link reaction feeds a 2C group into the Krebs cycle, which turns twice per glucose.MITOCHONDRIAL MATRIXpyruvate3ClinkCO2​reduced NADacetyl coenzyme A2C group carriedKrebscycle2C + 4CCoAreusedone turn gives2 CO2​3 reduced NAD1 reduced FAD1 ATPper glucosetwo pyruvate, so two link reactionsand two turns of the cyclewhere they go nextreduced NAD and FAD carry hydrogen tooxidative phosphorylationDo not memorise the acid names. Oxygen is not a reactant written inside the cycle.

NOT: acid names inside the cycle are not required, and oxygen is not a reactant written in the cycle.

  1. Both stages are in the matrix
  2. Decarboxylation releases CO₂
  3. Dehydrogenation reduces NAD and FAD
  4. Two turns per glucose

Two traps this diagram blocks

  • Do not recite named cycle acids unless the question gives them.
  • Do not say the lungs carry out the Krebs cycle.

From the diagram alone

Question

Describe the products of the link reaction and one role of coenzyme A. [3]

Show a model answer

The link reaction produces carbon dioxide and reduced NAD. Coenzyme A carries the remaining two-carbon acetyl group into the Krebs cycle.

Link reaction versus one Krebs turn
StageCarbonHydrogen carriers and ATP
Link, per pyruvate1 CO₂ removed1 reduced NAD; acetyl group to coenzyme A
Krebs, per turn2 CO₂ removedReduced NAD, reduced FAD, 1 substrate-level ATP
Per glucoseBoth stages happen twiceCytoplasmic glycolysis is extra and already done
EXAM TIPS & ADVICE

Make your reasoning visible

Build the explanation

X happens because Y, leading to Z. X: the stops when oxygen is absent. Y: oxygen is not a reactant inside the cycle, but without it the cannot reoxidise NAD and FAD. Z: has nowhere to put hydrogen, so the cycle stops. Incomplete: “Oxygen is used up inside the Krebs cycle.” Improved: “The cycle needs oxidised NAD and FAD. Those return only if the chain can pass electrons to oxygen.”

Name the reaction type

for CO₂. Dehydrogenation for or . for the small .

Matrix, not cytoplasm

If the question says “where”, is the cytoplasmic one. These two are mitochondrial.

Avoid this misconception

The claim: The Krebs cycle uses oxygen and produces most of the ATP directly.

The correction: Oxygen is the final acceptor on the electron transport chain, not a reactant written in the cycle. The cycle’s own ATP is the small substrate-level yield. Most ATP comes later from the reduced .

SPECIFICATION 7.3 · ORDER IT

Put the link reaction and Krebs cycle in order

After glycolysis, pyruvate is oxidised in the mitochondrial matrix. Order one turn, from pyruvate to the acceptor that lets the cycle turn again.

Order the steps

What to do

  1. Reorder the cards below: drag a card (on a touch screen, drag its number), tap a card then tap where it goes, or use the ↑ and ↓ arrows at its right.
  2. Press Check under the cards to mark each one green (right place) or red; the count shows how many are right.
  3. Stuck? Hint first outlines the first wrong place, then gives a clue, then places that step for you.
  4. Shuffle mixes the cards again; Start again returns them to the starting order. Keyboard: Space picks up, arrow keys move, Space drops.

One pyruvate from glycolysis enters a mitochondrion. Put the steps in order.

0 of 7 in the right place

The names of the acids in the cycle are not required. Several of the dehydrogenations are combined into fewer steps here; the hydrogen goes to the electron transport chain (7A 4).

RETRIEVE · APPLY · CHECK

Check your understanding

Try each question before opening the suggested answer.

Check your understanding (continued)

  1. Practice question

    Retrieval and explanation · suggested answer

    Where do the link reaction and the Krebs cycle take place?

    Show suggested answer

    In the matrix of the mitochondrion. Glycolysis is in the cytoplasm.

  2. Practice question

    Retrieval and explanation · suggested answer

    What happens to the carbon of pyruvate in the link reaction?

    Show suggested answer

    Decarboxylation removes it as carbon dioxide. The remaining two-carbon group is carried by coenzyme A into the Krebs cycle.

  3. Practice question

    Retrieval and explanation · suggested answer

    State three products of one turn of the Krebs cycle.

    Show suggested answer

    Carbon dioxide, reduced NAD, reduced FAD and ATP. Any three. The ATP is substrate-level.

  4. Practice question

    Retrieval and explanation · suggested answer

    Why does the cycle stop if the electron transport chain stops?

    Show suggested answer

    NAD and FAD are not regenerated, so dehydrogenation cannot continue.

STRETCH QUESTION

Take the idea further

Apply the same specification knowledge to an unfamiliar problem. Any extra assumptions are supplied in the question.

Stretch question

A question shows glucose labelled only in one carbon atom, and later finds labelled carbon dioxide. Assume that carbon survived glycolysis inside pyruvate. Which two stages could have released it, and which stage could not?

Show a hint

Glycolysis does not decarboxylate.

Explore the reasoning

The link reaction or the Krebs cycle could release it as CO₂, depending on which carbon of pyruvate it was. Glycolysis cannot: it does not remove carbon dioxide. You are not expected to track the exact carbon through named acids.

RECALL

Recall this lesson

Lesson recall questions

5 of 16 recall questions for 7.30 of 5 rated0 secure

Question 1 of 5: State where the link reaction and the Krebs cycle take place, in contrast to glycolysis.

017.3Keyword

Link reaction and Krebs

Practice question

Retrieval and explanation · suggested answer

State where the link reaction and the Krebs cycle take place, in contrast to glycolysis.

Try this from memory first.

Practise more of these specification points

Beyond the classroom

Put your biology to work

Explore where these ideas appear in the world. Enrichment, not extra required recall.

ResearchMedicine

The carbon dioxide in your breath was chemistry first

7A · The Krebs CycleNHLBI describes the lungs as the place where oxygen enters the blood and carbon dioxide leaves it. That is ventilation and gas exchange. The carbon dioxide itself was…Specification 7.3Read & use the scienceClose article

Why this matters

NHLBI describes the lungs as the place where oxygen enters the blood and carbon dioxide leaves it. That is ventilation and gas exchange. The carbon dioxide itself was produced by decarboxylation in cells. The lung page does not teach the Krebs cycle, and it does not treat breathing as cellular respiration. 7.3: carbon dioxide is formed by decarboxylation in the link reaction and the Krebs cycle, in mitochondria. A measured gas or ATP change cannot, on its own, identify every intermediate enzyme or show which step changed.

Back to the specification

Pearson Edexcel IAL Biology · Issue 2, February 2021 · Unit 5, pp. 35–38. The application extends beyond required recall.

  • 7.3 Link reaction and Krebs cycle: carbon dioxide, ATP and reduced coenzymes.
Read the Pearson specification

Use the science

Why is “I breathed out, so my lungs ran the Krebs cycle” incorrect?

Explore a possible response

Breathing exhales carbon dioxide that cells have already produced. The cycle runs in mitochondrial matrices, not in the lung airway.

Explore the source

ResearchMedicine

Carbon can leave before the chain begins

7A · The Krebs CycleThe NCI discussion of tumour metabolism follows carbon from glucose into pathways used for growth. It notes that changing the fate of pyruvate can change how much carbon…Specification 7.3Read & use the scienceClose article

Why this matters

The NCI discussion of tumour metabolism follows carbon from glucose into pathways used for growth. It notes that changing the fate of pyruvate can change how much carbon enters mitochondrial metabolism. This gives a real reason to keep 7.3 distinct from 7.4: the link reaction and Krebs cycle release carbon dioxide and supply reduced coenzymes, while the electron transport chain handles their electrons later. A change in carbon dioxide output might reflect substrate choice or pathway use; it does not locate a mutation by itself. The cancer setting is an application of carbon flow, not an extra Krebs intermediate to memorise.

Back to the specification

Pearson Edexcel IAL Biology · Issue 2, February 2021 · Unit 5, pp. 35–38. The application extends beyond required recall.

  • 7.3 Link reaction and Krebs cycle: carbon dioxide, ATP and reduced coenzymes.
Read the Pearson specification

Use the science

If less pyruvate enters the link reaction, what happens to its direct carbon dioxide output and to the supply of reduced coenzymes?

Explore a possible response

Both would tend to fall from that route: less pyruvate is decarboxylated, and less substrate reaches the reactions that reduce NAD and FAD. Other fuels could complicate a whole-cell measurement.

Explore the source

Browse all Unit 5 connections →
END OF THE LESSON

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