1A 4

Lipids

Build a triglyceride and distinguish saturated from unsaturated fatty acid chains.

YOUR SPECIFICATION

What you need to know

  • 1.5(i) synthesis: glycerol, three fatty acids, and ester bonds.
  • 1.5(ii)Differences between saturated and unsaturated lipids.
Pearson specification · Issue 2, p. 15

By the end, you should be able to…

  • Identify the components of a triglyceride.
  • Describe formation of three ester bonds.
  • Compare saturated, monounsaturated and polyunsaturated fatty acids.
SPECIFICATION-ALIGNED LEARNING

Build your understanding

A triglyceride has four starting molecules

A is made from one glycerol molecule and three fatty acid molecules. Glycerol has three hydroxyl (–OH) groups. Each fatty acid has a carboxyl (–COOH) group attached to a hydrocarbon chain.

A glycerol block with three fatty acid hydrocarbon chains attached, each by an ester bond. Three water molecules are released.glycerol3 fatty acidsester bond+ 3 H₂O released
One glycerol joined to three fatty acids by three ester bonds. Each condensation releases one water molecule.

A reaction between a hydroxyl group of glycerol and the carboxyl group of a fatty acid forms an . Repeating this at all three hydroxyl groups produces a triglyceride with three ester bonds and releases three water molecules.

Read the carbon chain

Top: a straight zigzag hydrocarbon chain labelled saturated, no C=C. Bottom: a zigzag chain with one carbon–carbon double bond where the chain bends, labelled unsaturated.saturated: no C=Cunsaturated: C=C makes a kink
A saturated chain has no C=C double bonds. An unsaturated chain has at least one C=C, which puts a kink in the chain.

A has no carbon–carbon double bonds in its hydrocarbon chain. A monounsaturated fatty acid has one C=C bond; a polyunsaturated fatty acid has more than one.

The carbonyl C=O bond in a fatty acid does not make it unsaturated in this . Look specifically for carbon–carbon double bonds. A triglyceride may contain different fatty acid chains, so inspect all three when given a diagram.

Structure and physical behaviour

Cis double bonds introduce bends into fatty acid chains. These generally make neighbouring chains pack less closely. Compared with similar saturated chains, this reduces the intermolecular attractions and tends to lower the melting point.

Many fats rich in saturated chains are solid at room temperature, while many oils rich in unsaturated chains are liquid. This is a useful tendency, not the definition of saturation: chain length and the mixture of molecules also affect physical behaviour. Triglycerides are largely and do not dissolve readily in water.

Follow the process

Glycerol has three –OH groups and each fatty acid has one –COOH group → a condensation reaction joins one –OH to one –COOH → an ester bond forms and one water molecule leaves → the same reaction at the other two –OH groups gives a triglyceride with three ester bonds and three water molecules released.

Saturation is decided afterwards, by inspecting each hydrocarbon chain for C=C bonds. Zero C=C bonds means saturated; one means monounsaturated; more than one means polyunsaturated. The biological assembly order is not the only valid written order: you may define the fatty acids first if the question asks about melting point.

One glycerol molecule, with three hydroxyl groups, joins three fatty acids by condensation. Three ester bonds form and three water molecules are released. Saturation is decided by carbon-carbon double bonds in the hydrocarbon chains. A triglyceride forms by three condensation reactionsOne glycerol joins three fatty acids, forming three ester bonds and releasing three water molecules.GLYCEROL3 FATTY ACIDSTRIGLYCERIDEH2​C–OHHOOCHC–OHHOOCH2​C–OHHOOCH2​C–O–OCHC–O–OCH2​C–O–OCcis C=C: unsaturated chainester bond (–COO–)3 ×+ 3H2​OThe bond is an ester bond, not glycosidic. Unsaturation means C=C in a chain, not the C=O of the ester.

NOT: the bond is ester, not glycosidic. C=O does not make a chain unsaturated.

  1. 1 glycerol + 3 fatty acids → 1 triglyceride + 3 H₂O
  2. Saturated: no C=C in the hydrocarbon chain
  3. One C=C: monounsaturated. More than one: polyunsaturated
  4. Cis C=C bends the chain and can lower the melting point

Two traps this diagram blocks

  • Do not call the bonds glycosidic or peptide bonds.
  • An oil is not the definition of unsaturated. Count the C=C bonds.

From the diagram alone

Question

Describe how a triglyceride is formed. [3]

Show a model answer

One glycerol reacts with three fatty acids. Each hydroxyl group of glycerol forms an ester bond with the carboxyl group of a fatty acid by condensation. Three water molecules are released.

Count carbon–carbon double bonds
Fatty acid typeC=C bonds per chainHydrogen saturation
SaturatedNoneMaximum for that carbon skeleton
MonounsaturatedOneFewer hydrogen atoms
PolyunsaturatedTwo or moreFewer hydrogen atoms
EXAM TIPS & ADVICE

Make your reasoning visible

Build the explanation

X happens because Y, leading to Z. X: a forms. Y: three reactions each make an between glycerol and a fatty acid. Z: three water molecules are released and the lipid is largely . Incomplete: “It is unsaturated because it is an oil.” Improved: “The chains contain C=C bonds, so the fatty acids are unsaturated; that can make packing less close and the melting point lower.” The improvement uses the bonds, not the appearance, as the definition.

Use the correct numbers

One glycerol + three fatty acids → one triglyceride + three water molecules. There are three ester bonds. Do not call them glycosidic bonds.

Key explanations

  • One C=C bond makes it monounsaturated. More than one makes it polyunsaturated.
  • The C=O in the carboxyl group is not counted when classifying saturation.

Avoid this misconception

The claim: A has no double bonds anywhere.

The correction: It has no carbon–carbon double bonds in its hydrocarbon chain. Its carboxyl group still contains a carbon–oxygen double bond.

SPECIFICATION 1.5(i) · ORDER IT

Order how a triglyceride forms

A triglyceride is built from one glycerol and three fatty acids by condensation reactions. Order the steps, from the separate molecules to the finished lipid.

Order the steps

What to do

  1. Reorder the cards below: drag a card (on a touch screen, drag its number), tap a card then tap where it goes, or use the ↑ and ↓ arrows at its right.
  2. Press Check under the cards to mark each one green (right place) or red; the count shows how many are right.
  3. Stuck? Hint first outlines the first wrong place, then gives a clue, then places that step for you.
  4. Shuffle mixes the cards again; Start again returns them to the starting order. Keyboard: Space picks up, arrow keys move, Space drops.

Put the steps in order, from glycerol and fatty acids to one triglyceride.

0 of 5 in the right place

The three fatty acids need not be the same. Phospholipids form the same way but with one fatty acid replaced by a phosphate group.

RETRIEVE · APPLY · CHECK

Check your understanding

Try each question before opening the suggested answer.

  1. Practice question

    Retrieval and explanation · suggested answer

    Describe the formation of a triglyceride, naming its bond type and the small molecule released.

    Show suggested answer

    One glycerol reacts with three fatty acids in condensation reactions. Three ester bonds form and three water molecules are released.

  2. Practice question

    Retrieval and explanation · suggested answer

    A fatty acid has two C=C bonds and one C=O bond. Classify it and explain your answer.

    Show suggested answer

    It is polyunsaturated because its chain contains more than one carbon–carbon double bond. The C=O bond is not counted when classifying saturation.

STRETCH QUESTION

Take the idea further

Apply the same specification knowledge to an unfamiliar problem. Any extra assumptions are supplied in the question.

Stretch question

A student argues that an oil with more C=C bonds must have a higher melting point because double bonds are strong. Explain the flaw.

Show a hint

Which interactions are overcome when a substance melts?

Explore the reasoning

Melting mainly overcomes attractions between molecules; it does not break their covalent C=C bonds. Cis double bonds can prevent close packing, reducing intermolecular attractions and lowering melting point relative to comparable saturated chains.

RECALL

Recall this lesson

Lesson recall questions

5 of 17 recall questions for 1.50 of 5 rated0 secure

Question 1 of 5: Name the bond formed between glycerol and a fatty acid in a triglyceride.

011.5Keyword

Triglycerides and saturation

Practice question

Retrieval and explanation · suggested answer

Name the bond formed between glycerol and a fatty acid in a triglyceride.

Try this from memory first.

Practise more of these specification points

Beyond the classroom

Put your biology to work

Explore where these ideas appear in the world. Enrichment, not extra required recall.

Pop Culture

What does an oil label really tell you?

1A · LipidsFood chemists can compare unsaturation through reactions at carbon–carbon double bonds. This connects a label such as “unsaturated fat” to a measurable molecular feature, rather than simply the…Specification 1.5(ii)Read & use the scienceClose article

Why this matters

Food chemists can compare unsaturation through reactions at carbon–carbon double bonds. This connects a label such as “unsaturated fat” to a measurable molecular feature, rather than simply the appearance of the food. A food label compresses molecular information into categories such as saturated and unsaturated. A double bond changes a fatty-acid chain, but the nutritional implications depend on the mixture, the amount consumed and what food replaces what. Chemists can describe the bonding precisely while researchers still investigate health outcomes. This distinction helps when an advert turns one structural feature into a promise of health: identifying a molecule is not the same experiment as measuring the effects of eating it.

Back to the specification

Pearson Edexcel IAL Biology · Issue 2, February 2021 · Unit 1, pp. 15–18. The application extends beyond required recall.

  • 1.5(ii) know the differences between saturated and unsaturated lipids
Read the Pearson specification

Use the science

A social-media post calls every liquid oil “healthy” because it is unsaturated. What can the molecular classification establish, and what can it not establish?

Explore a possible response

It can describe the presence of C=C bonds. On its own it cannot establish the overall health effect of a food or diet; amount consumed, other ingredients and evidence about outcomes also matter.

Explore the source

EnvironmentResearch

From used cooking oil to fuel

1A · LipidsUsed cooking oil can become a feedstock for biodiesel, but pouring it straight into an engine is not the same process. Triglycerides are chemically converted into smaller fatty-acid…Specification 1.5(i)Read & use the scienceClose article

Why this matters

Used cooking oil can become a feedstock for biodiesel, but pouring it straight into an engine is not the same process. Triglycerides are chemically converted into smaller fatty-acid esters and glycerol in a reaction called transesterification. You already know that triglycerides contain ester bonds linking fatty acids to glycerol; the industrial reaction rearranges those connections using an alcohol. It changes properties such as viscosity, which matters when a fuel must flow and spray reliably. Calling a fuel biological also does not establish its full environmental footprint: the feedstock, processing energy and competing land uses still matter.

Back to the specification

Pearson Edexcel IAL Biology · Issue 2, February 2021 · Unit 1, pp. 15–18. The application extends beyond required recall.

  • 1.5(i) know how a triglyceride is synthesised by the formation of ester bonds during condensation reactions between glycerol and three fatty acids
Read the Pearson specification

Use the science

Why is producing biodiesel a chemical change rather than simply melting a fat? Refer to triglyceride structure.

Explore a possible response

Melting changes physical state without changing covalent bonding. Transesterification changes ester connections and produces different molecules, including glycerol and fatty-acid esters.

Explore the source

Browse all Unit 1 connections →
END OF THE LESSON

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