P3.7

Pressure on solids

Indicative relationship: Activate 2 · Motion and Pressure
KS3 science lesson

Pressure on solids

Lesson focus: Pressure on a solid surface depends on and .

Learning objective

Calculate p = F/A, convert squared units correctly and explain design applications.

Build on earlier learning

Pressure in liquids

The same force-per-area definition now applies to solid contact.

You will be successful when you can…

  • State and rearrange p = F/A.
  • Use N and m².
  • Convert cm² correctly.
  • Explain area effects.
KEY VOCABULARY

Words that carry the science

contact area
Area through which surfaces transmit force.
normal force
Force perpendicular to a surface.
pascal
One newton per square metre.
square metre
Area of a one-metre by one-metre square.
inverse relationship
One quantity falls as another rises under controlled conditions.
BUILD YOUR UNDERSTANDING

Pressure divides force across area

01Pressure divides force across area

Pressure = normal force ÷ contact area and 1 Pa = 1 N/m².

For fixed force, smaller area gives greater pressure. Blades concentrate force; snowshoes spread it.

02Area conversions are squared

Because 1 m = 100 cm, 1 m² = 10,000 cm². Divide cm² by 10,000 to obtain m².

Convert before substituting. A calculator cannot detect a physically wrong unit conversion.

03Models need assumptions

The simple calculation assumes the force is normal and spread across the quoted area.

Soft surfaces and uneven tread change effective , so real values can be estimates.

The same downward force acts through a wide snowshoe and a narrow heel. Pressure tiles beneath the heel are more concentrated. A unit panel shows one square metre equals ten thousand square centimetres.same forcesame forcelarge arealower pressuresmall areahigher pressurep = F ÷ A1 Pa = 1 N/m²1 m² = 10,000 cm²cm² ÷ 10,000 = m²
Figure · For a fixed normal force, reducing contact area increases pressure. Area units must be squared: convert cm² to m² by dividing by 10,000.
Interactive model

Pressure on solids

Pressure = force ÷ area. The same weight spread over a bigger area gives a smaller pressure. That is why snowshoes stop you sinking into snow, and stiletto heels dent floors.

Weight 490 NSinks about 10 cm (illustrative)

Controls

Footwear
50 kg
Weight (force)490 N
Contact areaabout 300 cm²
Pressure1.63 N/cm² = 16 kPa

Areas are approximate; sinking depths are illustrative. 1 N/cm² = 10 000 N/m² = 10 kPa.

For the same weight, pressure falls as the area increases: double the area, half the pressure.05001000150020000510152025301.63 N/cm2Contact area / cm2Pressure / N/cm2
WORKED EXAMPLE

Pressure beneath a block

A 600 N block rests on 300 cm².

  1. p = F/A.
  2. 300 cm² ÷ 10,000 = 0.030 m².
  3. p = 600 ÷ 0.030.
  4. p = 20,000 Pa.

How to make the reasoning visible: The pressure is 20 kPa.

LEARN BY DOING

Compare contact pressures

Calculate before explaining design.

CaseForce / NArea / m²Pressure / Pa
Snowshoe7000.140?
Boot heel3500.0007?
Tank track80,0008?
Pin tip200.0000005?
  1. Calculate pressures.

  2. Explain one design.

RETRIEVE · APPLY · CHECK

Check your understanding

Answer from memory, then check against the suggested answer.

State the equation.

Define one pascal.

How many cm² in 1 m²?

Apply the idea

What happens when a brick rests on its smallest face?

Stretch and challenge

Why might a tank exert more pressure than a person despite wide tracks?

Exam Question Practice

P3.7Calculate5 marks

Exam Question Practice

Mark points shown after marking

A crate weighs 1800 N. Its base measures 60 cm by 50 cm.

Calculate the pressure the crate exerts on the floor, in Pa. Show your working.

(5)
Pa

Total for this question: 5 marks

Command word: Convert lengths before multiplying to find area.

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