2.37

2.37: Aerobic respiration equations

The word and balanced chemical symbol equations for aerobic respiration, interpreted through conservation of atoms and energy release.

LEARNING GOALS

By the end of this lesson

  • Recall the word equation for aerobic respiration.
  • Write and verify the balanced symbol equation.
  • Interpret the equation without treating respiration as one reaction.

BIG QUESTION

What can the aerobic-respiration equation prove—and what does it hide?

The equation tracks overall matter conversion, but it compresses a multistep pathway and does not show ATP stoichiometry.

The word equation names the overall substances

glucose + oxygen → carbon dioxide + water

Energy is released during the pathway, but energy and ATP are not material reactants or stoichiometric products in this chemical equation.

The balanced equation conserves atoms

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

Both sides contain six carbon atoms, twelve hydrogen atoms and eighteen oxygen atoms. Balance by changing coefficients, never the subscripts in a correct formula.

The equation summarises complete oxidation

Carbon atoms from glucose appear in carbon dioxide, and hydrogen atoms appear in water. Oxygen contributes to products through a sequence of reactions.

The equation shows overall inputs and outputs, not individual intermediates or the exact route of each atom through the pathway.

Respiration is not combustion in one step

Both respiration and combustion are exothermic oxidations, but respiration releases energy through enzyme-controlled stages at cellular temperatures.

Controlled steps allow some energy to be coupled to ATP formation rather than all being released rapidly as heat and light.

Reading the equation

Each feature provides specific evidence and has a boundary.

Meaning and limits of the aerobic equation
FeatureWhat it showsWhat it does not show
CoefficientsOverall molecular or molar ratios.Rate or number of pathway steps.
Balanced atomsConservation of matter.The route taken by each atom.
ArrowOverall direction of conversion.One instantaneous reaction.
Equation productsCarbon dioxide and water.A fixed universal ATP yield.
KEY TERMS

Language that earns precision

word equation
An equation naming reactants and products in words.
symbol equation
An equation using chemical formulae.
coefficient
A number before a formula showing relative amount.
oxidation
Loss of electrons or gain of oxygen; glucose is oxidised overall in aerobic respiration.
conservation of matter
Atoms are rearranged rather than created or destroyed.

Common misconceptions

Claim: ATP belongs after the arrow in the balanced chemical equation.

Correction: The specified material equation balances glucose, oxygen, carbon dioxide and water; ATP formation is coupled to the pathway.

Claim: The equation is balanced by changing O₂ to O₆.

Correction: Use coefficients; do not alter correct formulae.

Claim: One glucose molecule collides with six oxygen molecules in one step.

Correction: The overall equation summarises many enzyme-controlled reactions.

Claim: Respiration is uncontrolled burning inside cells.

Correction: It is a regulated, staged oxidation at cellular temperatures.

EXAM LANGUAGE

Match the answer to the command word

Recall

Place glucose and oxygen on the left; carbon dioxide and water on the right.

Balance

Count C, H and O independently after adding coefficients.

Explain

Refer to linked enzyme-controlled reactions when discussing the equation’s limitations.

CHECK YOUR UNDERSTANDING

Recall, apply, then justify

01Write2 marks

Write the word equation for aerobic respiration.

Hint

Two reactants and two products.

Suggested marking points
  • Glucose + oxygen.
  • Carbon dioxide + water in the correct product positions.
02Write2 marks

Write the balanced symbol equation for aerobic respiration.

Hint

One glucose requires six oxygen molecules.

Suggested marking points
  • C₆H₁₂O₆ + 6O₂.
  • 6CO₂ + 6H₂O.
03Verify3 marks

Verify that the symbol equation is balanced.

Hint

Count each element on both sides.

Suggested marking points
  • Six carbon atoms on each side.
  • Twelve hydrogen atoms on each side.
  • Eighteen oxygen atoms on each side.
STRETCH AND CHALLENGE

Explain why the balanced equation cannot be used to state an exact ATP yield for every cell.

Planning hint

Separate atom balance from pathway efficiency.

What a strong design includes
  • The equation tracks overall material conversion, not ATP-coupling steps.
  • Cells can use different shuttle systems and pathway efficiencies.
  • Some energy is released as heat.
  • Proton leakage and cellular conditions vary.
  • ATP may also be consumed in associated transport processes.
  • Therefore atom balance does not determine one universal ATP yield.
END OF THE LESSON

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Practise 2.37: 15 recall questions · 8 exam questions